Curiosity, learning and homework help
26/05/2024
Language: FR | ENG

:

### MEMBERS

 Come to discuss on the forum!■ FAST and FREE signup. ■ 😀 Access to discussion forums 😀 Help for HOMEWORKS, support in COMPUTER SCIENCE, help for learning FRENCH and ENGLISH, discussion on your INTERESTS and HOBBIES...Following numerous requests, a new forum on PIPENET Vision has been created!

### Looking for an English version of this section?

This section is in French because the contents are in French. If you prefer the English version of this section, click on the link below.
However, the contents in the French and the English sections are not necessarily the same!

Définition de base des fonctions trigonométriques
La fonction cosinus

Valeurs particulières de la fonction cosinus (cos) :

$$\displaystyle cos(0^{\circ})=cos(0)=1$$

$$\displaystyle cos(30^{\circ})=cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}$$

$$\displaystyle cos(45^{\circ})=cos(\frac{\pi}{4})=\frac{\sqrt{2}}{2}$$

$$\displaystyle cos(60^{\circ})=cos(\frac{\pi}{3})=\frac{1}{2}$$

$$\displaystyle cos(90^{\circ})=cos(\frac{\pi}{2})=0$$

$$\displaystyle cos(x + 2\pi)=cos(x)$$

La fonction sinus

Valeurs particulières de la fonction sinus (sin) :

$$\displaystyle sin(0^{\circ})=sin(0)=0$$

$$\displaystyle sin(30^{\circ})=sin(\frac{\pi}{6})=\frac{1}{2}$$

$$\displaystyle sin(45^{\circ})=sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}$$

$$\displaystyle sin(60^{\circ})=sin(\frac{\pi}{3})=\frac{\sqrt{3}}{2}$$

$$\displaystyle sin(90^{\circ})=sin(\frac{\pi}{2})=1$$

$$\displaystyle sin(x + 2\pi)=sin(x)$$

La fonction tangente

Valeurs particulières de la fonction tangente (tan) :

$$\displaystyle tan(0^{\circ})=tan(0)=0$$

$$\displaystyle tan(30^{\circ})=tan(\frac{\pi}{6})=\frac{\sqrt{3}}{3}$$

$$\displaystyle tan(45^{\circ})=tan(\frac{\pi}{4})=1$$

$$\displaystyle tan(60^{\circ})=tan(\frac{\pi}{3})=\sqrt{3}$$

La fonction tangente n'est pas définie en $$\displaystyle \frac{\pi}{2}$$ ($$\displaystyle 90^{\circ}$$).

$$\displaystyle tan(x + \pi)=tan(x)$$

Relations entre les fonctions trigonométriques

Principales relations entre les fonctions trigonométriques :

$$\displaystyle cos^2(x)+sin^2(x)=1$$

$$\displaystyle tan(x)=\frac{sin(x)}{cos(x)}$$

$$\displaystyle \frac{1}{cos^2(x)}=1+tan^2(x)$$

$$\displaystyle cotan(x)=\frac{1}{tan(x)}$$

$$\displaystyle cotan(x)=\frac{cos(x)}{sin(x)}$$

$$\displaystyle \frac{1}{sin^2(x)}=1+cotan^2(x)$$